MCQ
The increasing order of nucleophilicity of the following nucleophiles is

$(a)\,\,CH_3CO_2^-$                                                    $(b)\,\,H_2O$
$(c)\,\,CH_3SO_3^-$                                                    $(d)\,\,\bar OH$

  • A
    $(b) < (c) < (a) < (d)$
  • $(a) < (d) < (c) < (b)$
  • C
    $(d) < (a) < (c) < (b)$
  • D
    $(b) < (c) < (d) < (a)$

Answer

Correct option: B.
$(a) < (d) < (c) < (b)$
b
As electronegativity of the central atom decreases, its nucleophilicity increases. Here,  carbon has the least electronegativity. So, $C H_{3}^{-}$ will have the highest nucleophilicity.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free