MCQ
The internal energy of an ideal gas increases during an isothermal process when the gas is
- ✓Expanded by adding more molecule to it.
- BExpanded by adding more heat to it.
- CExpanded against zero pressure.
- DCompressed by doing work on it.
✓
Answer
Correct option: A.
Expanded by adding more molecule to it.
a
Internal energy of isotherma process
Internal energy of isotherma process
$v =\frac{ f }{2} \times NKT$
$\Rightarrow v \propto NT$
$T$ is constant (Isothermal process $v \propto N$ i.e., Internal energy increases by increasing number of molecules $( N )$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Oxidation number of fluorine in $\ce{F_2O}$ is :
→Assuming that water vapour is an ideal gas, the internal energy change $(\Delta U)$ when $1\, mol$ of water is vapourised at $1\, bar$ pressure and $100\,^oC,$ (given : molar enthalpy of vapourisation of water at $1\, bar$ and $373\, K = 41\, kJ\, mol^{-1}$ and $R = 8.3\, J\, mol^{-1}\, K^{-1}$) will be .............. $\mathrm{kJ\,mol}^{-1}$
→The correct nomenclature for the following compound is:
A hydrocarbon has $C=85.72\%$ and remaining $H$. The hydrocarbon is
→Which of the following has highest melting point
$2 \,mol$ of $FeSO_4$ are oxidised by $'X'\, mol$ of $KMnO_4$ whereas $2\, mol$ of $FeC_2O_4$ are oxidised by $'Y'\, mol$ of $KMnO_4$. The ratio of $X$ and $Y$ is
→Which of the following is a characteristic of matter?
Formation of $2-$butene from $2-$bromobutane is according to
→Which of the following compound is optically active?
The element that does $NOT$ show catenation is
→