Application of Derivatives — Maths STD 12 Science — Question
Gujarat BoardEnglish MediumSTD 12 ScienceMathsApplication of Derivatives1 Mark
Question
The interval in which y = x2 e–x is increasing is
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Answer
It is given that y = x2 e–x then $\frac{d y}{d x}$ = 2xe-x - x2e-x = xe-x (2-x) Now, if $\frac{d y}{d x}$ = 0 $\Rightarrow$ x = 0 and x =2 The points x = 0 and x= 2 divide the real line into three disjoint intervals ie, (-$\infty$,0), (0,2) and (2,$\infty$). In interval (-$\infty$,0) and (2,$\infty$), f’(x) < 0 as e-x is always positive. Therefore, f is decreasing on (-$\infty$,0) and (2,$\infty$). In interval (0,2), f’(x) > 0 Therefore, f is strictly increasing in interval (0.2).
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