Question
The interval in which y = x2 e–x is increasing is

Answer

It is given that y = x2 e–x
then  $\frac{d y}{d x}$ = 2xe-x - x2e-x = xe-x (2-x)
Now, if  $\frac{d y}{d x}$ = 0
$\Rightarrow$ x = 0 and x =2
The points x = 0 and x= 2 divide the real line into three disjoint intervals ie, (-$\infty$,0), (0,2) and (2,$\infty$).
In interval (-$\infty$,0) and (2,$\infty$),
f’(x) < 0 as e-x is always positive.
Therefore, f is decreasing on (-$\infty$,0) and (2,$\infty$).
In interval (0,2), f’(x) > 0
Therefore, f is strictly increasing in interval (0.2).

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free