MCQ
The ionic radii $(\mathop A\limits^o )$ of $C^{4-}$ and $O^{2-}$ respectively are $2.60$ and $1.40 .$ The ionic radius of the isoelectronic ion $N^{3-}$ would be........$\mathop A\limits^o $
- A$131$
- B$2.83$
- ✓$1.71$
- D$2.63$
✓
Answer
Correct option: C.
$1.71$
c
$C^{4-}, N^{3-}$ and $O^{2-}$ are isoelectronic species.
$C^{4-}, N^{3-}$ and $O^{2-}$ are isoelectronic species.
The ionic radius of isoelectronic species decreases with increase in nuclear charge.
Hence, the order of ionic radius is
Species: $C^{4-}>N^{3-}>O^{2-}$
Ionic radii $(\mathop A\limits^o) : 2.60>1.71>1.40$
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