MCQ
Under the same condition, how many $ml$ of $1M\, KOH$ and $0.5\,M\, H_2SO_4$ solution, respectively, when mixed to from a total volume of $100\, ml$, produce maximum rise in temperature ?
  • A
    $67, 33$
  • B
    $33,67$
  • C
    $40, 60$
  • $50, 50$

Answer

Correct option: D.
$50, 50$
d
Rise in temperature will be highest if the ectent of neutralixation reaction is higher due to which the heat evolved will be greater in quantity.

$g$ equation = equivalent = Volume $\times$ normality

normality = molarity $\times n-$ factor

For newtralisation reaction,

$g$ equation of acid $=g$ equation of base

$v \times 0.5 \times 2=(100-v) \times 1 \times 1$

$\Rightarrow v=100-v$

$\Rightarrow 2 v=100$

$\Rightarrow v=50 ml$

$\therefore$ Volume of $H_2SO_4=v 50 ml$

and, Volume of $K O H=100-v=100-50=50 ml$

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