MCQ
The ionic radii of $Li^+ , Be^{2+}$ and $B^{3+}$ follow the order
- A$Be^{2+} > B^{3+} > Li^+$
- B$Li^+ >B^{3+} >Be^{2+}$
- C$B^{3+} > Be^{2+} > Li^+$
- ✓$Li^+ > Be^{2+} > B^{3+}$
✓
Answer
Correct option: D.
$Li^+ > Be^{2+} > B^{3+}$
d
While the $L i^{+}$ will be the largest because the nuclear charge on it (+1) is least out of the three.
While the $L i^{+}$ will be the largest because the nuclear charge on it (+1) is least out of the three.
$B e^{2+}$ will have the size in between the two cations.
Therefore, the order of ionic radius is $B^{3+}<$$B e^{2+}$
Hence option $D$ is correct
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