MCQ
The ionization constant of a certain weak acid is ${4}$. What should be the [salt] to [acid] ratio if we have to prepare a buffer with $ pH = 5$ using this acid and one of the salts
- A$1:10$
- ✓$10:1$
- C$5:4$
- D$4:5$
$5 = - \log {10^{ - 4}} + \log \frac{{[{\rm{salt}}]}}{{{\rm{[acid]}}}}$
$\log \frac{{[{\rm{salt}}]}}{{{\rm{[acid]}}}} = 1$
$\frac{{[{\rm{salt}}]}}{{{\rm{[acid]}}}} = {\rm{antilog}}\,1 = 10:1$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$2MnO_4^ - + 5{C_2}O_4^ - + 16{H^ + } \to 2M{n^{ + + }} + 10C{O_2} + 8{H_2}O$
Here $20\, mL$ of $0.1\, M\, KMnO_4$ is equivalent to
Statement $I :$ $o-$Nitrophenol is steam volatile due to intramolecular hydrogen bonding.
Statement $II :$ $o-$Nitrophenol has high melting due to hydrogen bonding.
In the light of the above statements, choose the most appropriate answer from the options given below
