MCQ
The $\text{IUPAC}$ name is :

- A$1-$ phenyl $-1-$ acetyloxyethane
- B$1-$ acetoxyeihylbenzene
- ✓$1-$ phenylethyl ethanoate
- D$1-$ methylbenzyl acetate

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Reason : In presence of $H_2SO_4$, $HNO_3$ acts as a base and produces $NO_2^+$ ions.

$A.$ For 1 s orbital, the probability density is maximum at the nucleus.
$B.$ For $2 s$ orbital, the probability density first increases to maximum and then decreases sharply to zero.
$C.$ Boundary surface diagrams of the orbitals encloses a region of $100 \%$ probability of finding the electron.
$D.$ $p$ and d-orbitals have $1$ and $2$ angular nodes respectively.
$E.$ Probability density of p-orbital is zero at the nucleus.
(Given : $R =8.3 \,J \,K ^{-1}\, mol ^{-1}$ )