Question
The $\text{IUPAC}$ name of $[\ce{Ni(CO)4}]$ is :
✓
Answer
The $\text{IUPAC}$ name of $\ce{Ni(CO)4}$ is Tetracarbonyl nickel $(0)$ since the oxidation state of carbonyl ligand is $0,$ so $Ni$ will also be $0$ and four ligand are bonded to central metal atom.
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