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6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
The $\mathrm{K}_{\mathrm{sp}}$ for the following dissociation is $1.6 \times 10^{-5}$

$\mathrm{PbCl}_{2(\mathrm{s})} \rightleftharpoons \mathrm{Pb}_{(\mathrm{ag})}^{2+}+2 \mathrm{Cl}_{(\mathrm{aq})}^{-}$

Which of the following choices is correct for a mixture of $300\; \mathrm{mL}\;\; 0.134 \;\mathrm{M} \;\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}$ and $100\; \mathrm{mL}\;\; 0.4\; \mathrm{M}\; \mathrm{NaCl} ?$

  • A
    $\mathrm{Q} < \mathrm{K}_{\mathrm{sp}}$
  • ✓
    $\mathrm{Q} > \mathrm{K}_{\mathrm{sp}}$
  • C
    $\mathrm{Q} = \mathrm{K}_{\mathrm{sp}}$
  • D
    Not enough data provided
✓

Answer

Correct option: B.
$\mathrm{Q} > \mathrm{K}_{\mathrm{sp}}$
b
$\left[\mathrm{Pb}^{2+}\right] =\frac{300 \times 0.134}{400}$

$=1.005 \times 10^{-1} \mathrm{M}$

$\left[\mathrm{C}^{-}\right] =\frac{100 \times 0.4}{400}$

$=10^{-1} \mathrm{M}$

$\mathrm{PbCl}_{2(3)} \rightleftharpoons \mathrm{Pb}_{(a q)}^{+2}+2 \mathrm{Cl}_{(aq.)^{2}}^{+2}$

$\mathrm{Q}=\left[\mathrm{Pb}^{2+}\right] \times\left[\mathrm{Cl}^{-}\right]^{2}$

$=1.005 \times 10^{-3} > \mathrm{k}_{\mathrm{sp}}$

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