Question
The $\mathrm{K}_{\mathrm{sp}}$ of $\mathrm{Ag}_2 \mathrm{CrO}_4 \mathrm{~AgCl}, \mathrm{AgBr}$ and Agl are respectively, $1.1 \times 10^{-12}, 1.8 \times 10^{-10}, 5.0 \times 10^{-13}, 8.3 \times 10^{-17}$, which one of the following salts will precipitate first $\mathrm{AgNO}_3$ solution is adding to a solution containing equal mole of $\mathrm{NaCl}, \mathrm{NaBs}$, NaI and $\mathrm{Na}_2 \mathrm{CrO}_4$.

Answer

Agl will precipitate first because $K_{\text {sp }}$ of Agl is lowest, therefore, ionic product will exceed the solubility products easily.

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