MCQ
The largest oxidation number exhibited by an element depends on its outer electronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number?
  • A
    $3 d^1 4 s^2 $
  • B
    $ 3 d ^34 s ^2 $
  • C
    $ 3 d^5 4 s^1 $
  • $ 3 d^5 4 s^2$

Answer

Correct option: D.
$ 3 d^5 4 s^2$
Highest $O.N$. of any transition element $= (n – 1)d$ electrons $+ns$ electrons. Therefore, larger the number of electrons in the $3d$ orbitals, higher is the maximum $O.N$.
  1. $ 3 d^1 4 s^2=3 $
  2. $ 3 d^2 4 s^2=3+2=5 $
  3. $ 3 d^5 4 s^1=5+1=6 $
  4. $ 3 d^5 4 s^2=5+2=7$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free