The length of the wire shown in figure between the pulleys is $1.5\, m$ and its mass is $12.0\,g$. The frequency of vibration with which the wire vibrates in three loops forming antinode at the mid point of the wire is $(g = 9.8 \,m/s^2)$
Medium
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$V=\sqrt{\frac{T}{\mu}}=\sqrt{\frac{T}{m / l}}=\sqrt{\frac{90 \times 1.5}{12 \times 10^{-3}}}=106 \mathrm{\,m} / \mathrm{s}$
$n=\frac{3 V}{2 l}=\frac{3 \times 106}{2 \times 1.5}=106 \mathrm{\,Hz}$
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