The limbs of a $U$ -tube glass are lowered into vessels $A$ and $B, A$ containing water. Some air is pumped out through the top of the tube $C$. The liquids in the left hand limb $A$ and the right hand limb $B$ rise to heights of $10\, cm$ and $12\, cm$ respectively. The density of liquid $B$ is ........ $g/cm^3$
Medium
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Equating pressure at the surface on both vessel
$\rho_{w} g \times \frac{10}{100}=\rho_{B} g \times \frac{12}{100} \Rightarrow \rho_{B}=\frac{10}{12} \rho_{w}$
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