The limiting molar conductivity ^o for NaCl, KBr and KCl are 126,… - Vidyadip

MCQ

The limiting molar conductivity $\mathop \Lambda \limits^o $ for $NaCl, KBr$ and $KCl$ are $126, 152$ and $150 \,S\,cm^2 \,mol^{-1}$ respectively. The $\mathop \Lambda \limits^o $ for $NaBr$ is (in $S\, cm^2\, mol^{-1}$).

A
$302$
B
$176$
C
$278$
✓
$128$

✓

Answer

Correct option: D.

$128$

d
The limiting molar conductivities of $NaCl , KBr$ and $KCl$ are $126,152$ and $150\, S\,cm ^{2} \,mol ^{-1}$ respectively.

The limiting molar conductivity $\Lambda^{\circ}$ for $NaBr$ is calculated by the following expression.

$\lambda_{N a B r}^{\infty}=\lambda_{N a C l}^{\infty}+\lambda_{K B r}^{\infty}-\lambda_{K C l}^{\infty}$

$\lambda_{N a B r}^{\infty}=126+152-150$

$=128 \,S\,cm ^{2} \,mol ^{-1}$

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