MCQ
The locus of a point, whose abscissa and ordinate are always equal is:
- Ax - y = 0
- Bx + y = 1
- Cx + y + 1 = 0
- DNone of the above
The locus of a point, whose abscissa and ordinate are always equal is:
Solution:
Let the abscissa and ordinate of a point “P” be (x, y)
Given condition: Abscissa = Ordinate
(i.e) x = y
The locus of a point is x - y = 0.
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The area of the circle centred at (1, 2) and passing through (4, 6) is:
$5\pi$
$10\pi$
$25\pi$
none of these.
If A lies in the second quadrant and $3\tan\text{A}+4=0,$ then the value of $2\cot\text{A}-5\cos\text{A}+\sin\text{A}$ is equal to:
$\frac{-53}{10}$
$\frac{23}{10}$
$\frac{37}{10}$
$\frac{7}{10}$