Question
The logic circuit shown below has the input waveforms '$A$' and '$B$' as shown. Pick out the correct output waveform. 

Answer

Here $y=(\overline{\bar{A}+\bar{B}})=\bar{\bar{\underset{\scriptscriptstyle\centerdot}{A}}}\cdot \bar{\bar{B}}=A\cdot B$

Thus it is an $AND$ gate for which truth table is

$\begin{array}{|c|c|c|}\hline A & {B} & {y} \\ \hline 0 & {0} & {0} \\ \hline 0 & {1} & {0} \\ \hline 1 & {0} & {0} \\ \hline 1 & {1} & {1} \\ \hline\end{array}$

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