The magnetic moment of $\ce{[Cu(NH_3)_4]^{2+}}$ was found to be $1.73 \ B.M.$ The number of unpaired electrons in the complex is$:$
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Magnetic moment of a complex having n-unpaired electrons is given by$:\sqrt{\text{n(n+2)}}$
where $n$ is the number of unpaired electrons.
$\sqrt{\text{n(n+2)}}=1.73$
$∴ \text{n}=1.$
where $n$ is the number of unpaired electrons.
$\sqrt{\text{n(n+2)}}=1.73$
$∴ \text{n}=1.$
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