PART - 1 CH - 3 Motion in a Plane — Physics STD 11 Science — Question
Rajasthan BoardEnglish MediumSTD 11 SciencePhysicsPART - 1 CH - 3 Motion in a Plane1 Mark
Question
The maximum horizontal range of a projected object is R. What is maximum height it reaches?
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Answer
If $\theta=45^{\circ}$ then $\begin{aligned} H & =\frac{1}{4}\left(\frac{u^2}{g}\right) \\ R_{\max } & =\frac{u^2}{g} \\ H & =\frac{R_{\max }}{4} \end{aligned}$
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