MCQ
The maximum number of electrons that can be accommodated in a $3d$ subshell is
- A$2$
- ✓$10$
- C$6$
- D$14$
There are $5$ sub-levels in a $d$ orbital, each one can have a maximum $2$ electrons.
Hence, $5$ sub-levels can have a maximum of $10$ electrons.
Thus,$s, p, d$ and $f$ orbitals can accommodate a maximum of $2,6,10$ an $14$ electrons.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


$\mathop { - CH{{(C{H_3})}_2}}\limits_1 \,\,\,\,\,\,\,\,\,\,\,\mathop { - C{H_2}C{H_2}Br}\limits_2 \,\,\,\,\,\,\,\,\,\,\mathop{ - C{H_2}Br}\limits_3 \,\,\,\,\,\,\,\,\,\mathop{ - C{{(C{H_3})}_3}}\limits_4$
$I = II = III = IV$
