The maximum number of possible interference maxima for slitsepara… - Vidyadip

MCQ

The maximum number of possible interference maxima for slitseparation equal to twice the wavelength in Young's double-slit experiment is

A
Infinite
B
Five
✓
Three
D
Zero

✓

Answer

Correct option: C.

Three

The interference fringes for two slits are hyperbolic.

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