
$\mathrm{V}_{\mathrm{ab}}=\frac{12}{9} \times 3=4 \mathrm{\,volt}$
$\mathrm{R}_{\mathrm{ab}}=8+\frac{6 \times 3}{9}=8+2=10\, \Omega$


Reason : A point charge when released from rest in a region having only electrostatic field always moves along electric lines of force.

