MCQ
The maximum solution of the objective function lies :
- Ain feasible region
- ✓at the corner of the feasible region
- Chas no feasible region
- Dnone of the above.
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$\frac{19}{8}$
$\frac{8}{19}$
$\frac{19}{2}$
$\frac{3}{4}$
$f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}
{\left| x \right| + \left[ x \right],}&{ - 1 \leq x < 1} \\
{x + \left| x \right|,}&{1 \leq x < 2} \\
{x + \left| x \right|,}&{2 \leq x \leq 3}
\end{array}} \right.$
where $[t]$ denotes the greatest integer less than or equal to $t$. Then, $f$ is discontinuous at: