The maximum wavelength of radiation emitted at $2000\;K$is $4\mu m$. What will be the maximum wavelength of radiation emitted at $2400\,K$ is ...... $\mu m$
Medium
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(a) $\therefore $$\frac{{{\lambda _{{m_2}}}}}{{{\lambda _{{m_1}}}}} = \frac{{{T_1}}}{{{T_2}}}$$ \Rightarrow {\lambda _{{m_2}}} = \frac{{2000}}{{2400}} \times 4 = 3.33\;\mu m$
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