The mean free path of electrons in a metal is $4 \times 10^{-8} \;m$. The electric field which can give on an average $2 \;eV$ energy to an electron in the metal will be in units of $V / m$
  • A$8 \times 10^7$
  • B$5 \times 10^7$
  • C$5 \times 10^{-11}$
  • D$8 \times 10^{-11}$
AIPMT 2009, Medium
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