In an adjoining figure are shown three capacitors ${C_1}$,${C_2}$ and ${C_3}$ joined to a battery. The correct condition will be (Symbols have their usual meanings)
c (c) ${Q_1} = {Q_2} + {Q_3}$ because in series combination charge is same on both the condenser and $V = {V_1} + {V_2}$ because in parallel combination ${V_2} = {V_3}.$
Hence $V = {V_1} + {V_2}$
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The material filled between the plates of a parallel plate capacitor has resistivity $200 \Omega \, {m}$. The value of capacitance of the capacitor is $2\, {pF}$. If a potential difference of $40 \,{V}$ is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is
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