MCQ
The median class for the data given below is:
Class20- 4040 - 6060 - 8080 - 100100 - 120
Frequency1012141317
  • A
    80 - 100
  • 60 - 80
  • C
  • D
    40 - 60

Answer

Correct option: B.
60 - 80
(B) 60 - 80
Explanation: Total frequencies (N) = 10 + 12 + 14 + 13 + 17= 66
So, $\frac{N}{2}=\frac{66}{2}=33$
c.f. Just greater than 33 is 36 and the corresponding class is 60 - 80
hence, median class = 60 - 80

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