Question
The minimum angular separation between two stars is $4 \times 10^6 rad$ when a telescope is used to observe them with an objective of aperture $16 cm$. Find the wavelength of the light.

Answer

Data : $\theta=4 \times 10^{-6} rad , D=16 cm =0.16 m$
$\theta=\frac{1.22 x}{D}$
$\therefore$ The wavelength of the light used.
$
\lambda=\frac{D \theta}{1.22}-\frac{0.16 \times 4 \times 10^{-6}}{1.22}-5.246 \times 10^{-7} m
$

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