MCQ
The minimum value of $3\cos x + 4\sin x + 5$ is
  • A
    $5$
  • B
    $9$
  • C
    $7$
  • $0$

Answer

Correct option: D.
$0$
d
(d) The minimum value of $3\cos x + 4\sin x$ is $ - \sqrt {{3^2} + {4^2}} = - 5$

Hence the minimum value of $3\cos x + 4\sin x + 5$

$ = - 5 + 5 = 0$.

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