The minimum value of (8sec^2 + 2cos^2 ) is equal to :- - Vidyadip

MCQ

The minimum value of $(8sec^2 \theta + 2cos^2 \theta)$ is equal to :-

✓
$10$
B
$16$
C
$8$
D
None

✓

Answer

Correct option: A.

$10$

a
Minimum value occurs
at $\theta = 0^o$
$8 + 2 = 10$

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