MCQ
The modulation index for an $A.M.$ wave having maximum and minimum peak to peak voltages of $14\,mV$ and $6\,mV$ respectively is :
- A$1.4$
- ✓$0.4$
- C$0.2$
- D$0.6$
✓
Answer
Correct option: B.
$0.4$
b
$\mu=\text { modulation index }=\frac{A_{\max }-A_{\min }}{A_{\max }+A_{\min }}$
$\mu=\text { modulation index }=\frac{A_{\max }-A_{\min }}{A_{\max }+A_{\min }}$
$=\frac{14-6}{14+6}=0.4$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The number of molecules in a gas at pressure $1.64 \times {10^{ - 3}}$atmospheres and temperature $200\, K$ having the volume $1 \,cc$ are
→A ring takes time ${t_1}$ in slipping down an inclined plane of length $L$ and takes time ${t_2}$ in rolling down the same plane. The ratio $\frac{{{t_1}}}{{{t_2}}}$ is
→The magnetic moment produced in a substance of $1\,gm$ is $6 \times {10^{ - 7}}\,ampere - metr{e^2}.$ If its density is $5\,gm/c{m^3},$ then the intensity of magnetisation in $A/m$ will be
→A bob of mass $'m'$ suspended by a thread of length $l$ undergoes simple harmonic oscillations with time period ${T}$. If the bob is immersed in a liquid that has density $\frac{1}{4}$ times that of the bob and the length of the thread is increased by $1 / 3^{\text {rd }}$ of the original length, then the time period of the simple harmonic oscillations will be :-
→A rod of length $2m$ rests on smooth horizontal floor. If the rod is heated from $0^o C$ to $20^o C$. Find the longitudinal strain developed? $(\alpha = 5 × 10^{-5}/^o C)$
→The scale on a steel metre stick is calibrated at $20^o\,C$.The error in the reading of $50\,cm$ at $30^o\,C$ is: (take linear expansion coefficient of steel $= 1.0 \times 10^{-5} / ^oC)$
→$^{22}Ne$ nucleus after absorbing energy decays into two $\alpha - $ particles and an unknown nucleus. The unknown nucleus is
→Two stones of masses $m$ and $2\,m$ are whirled in horizontal circles, the heavier one in a radius $\frac{r}{2}$ and the lighter one in radius $r.$ The tangential speed of lighter stone is $n$ times that of the value of heavier stone when they experience same centripetal forces. The value of $n$ is
→For what value of unknown resistance $X$, the potential difference between $B$ and $D$ will be zero in the circuit shown in the figure ............... $\Omega$
→Due to addition of impurities, the modulus of elasticity