MCQ
The momentum (in $kg-m/s$ ) of photon having $6\,\,MeV$ energy is
  • $3.2 \times 10^{-21}$
  • B
    $2.0$
  • C
    $1.6 \times 10^{-21}$
  • D
    $3.2 \times 10^{-18}$

Answer

Correct option: A.
$3.2 \times 10^{-21}$
a
$E=6\, MeV =6 \times 10^6 \,eV$

$E=\frac{h c}{\lambda}$

$\lambda =\frac{h}{P}$

$p =\frac{h}{\lambda}=\frac{E}{C}$

$=\frac{26 \times 10^6 \times 1.6 \times 10^{-13}}{3 \times 10^7}$

$=3.2 \times 10^{-21}$

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