Excess of KI reacts with CuS O_4 solution and then N a_2 S_2 O_3 … - Vidyadip

MCQ

Excess of $KI $ reacts with $CuS{O_4}$ solution and then $N{a_2}{S_2}{O_3}$ solution is added to it. Which of the statements is incorrect for this reaction

A
$N{a_2}{S_2}{O_3}$ is oxidised
✓
$Cu{I_2}$ is formed
C
$C{u_2}{I_2}$is formed
D
Evolved ${I_2}$ is reduced

✓

Answer

Correct option: B.

$Cu{I_2}$ is formed

(b)$2\mathop {KI}\limits^{\,\, - 1} + 2CuS{O_4} \to {\mathop I\limits^{\rm{O}} _2} + C{u_2}{I_2} + 2{K_2}S{O_4}$
${\mathop I\limits^{\rm{O}} _2} + 2N{a_2}\mathop {{S_2}}\limits^{ + 2} {O_3} \to \mathop {N{a_2}}\limits^{ + 2.5} {S_4}{O_6} + \mathop {2NaI}\limits^{\,\,\,\,\, - 1} $

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