Download App

STD 12 - p -Block elements - ll — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - p -Block elements - ll4 Marks
MCQ
The more activeness of fluorine is due to
  • ✓
    $F-F$ bond has less energy
  • B
    ${F_2}$ is gas at normal temperature
  • C
    Its electronic bond is maximum
  • D
    $F-F$ bond has more energy
✓

Answer

Correct option: A.
$F-F$ bond has less energy
a
The more activeness of fluorine is because $F - F$ bond has less energy.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

$[ Fe ( CN )_{6}]^{3-}$ should be an inner orbital complex. Ignoring the pairing energy, the value of crystal field stabilization energy for this complex is $(-)\;\dots \;\Delta_{\circ}$.
→
Which of the following will be coloured ion :
→
Iodoform can be obtained on warming $NaOH$ and iodine with
→
What is the molar solubility of $Al(OH)_3$ in $0.2\, M\, NaOH$ solution? Given that, solubility product of $Al(OH)_3 = 2.4 \times 10^{-24}$ 
→
What will be the sum of $pH$ and $pOH$ in an aqueous solution ?
→
Acidified $K_2Cr_2O_7$ solution turns green when $Na_2SO_3$ is added to it. This is due to the formation of
→
Which of the following is an electron deficient molecule?
→
Which of the following molecule contains both ionic and covalent bond
→
The bond dissociation energy is highest for
→
A certain buffer solution contains equal concentration of $X^-$ and $HX$. The $K_b$ for $X^-$ is $10^{-10}$. The $pH$ of the buffer is
→