- A

- B

- C

- ✓






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$(1)$ $\begin{matrix}
C{{H}_{3}} \\
|\,\,\,\,\,\, \\
ZNH\,C\,HC{{O}_{2}}H \\
\end{matrix}$ $(2)$ $\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{H}_{2}}N\,C\,HC{{O}_{2}}C{{H}_{2}}{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
$(3)$ $\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}{{C}_{6}}{{H}_{5}} \\
|\,\,\,\,\, \\
ZNH\,C\,HC{{O}_{2}}H \\
\end{matrix}$ $(4)$ $\begin{matrix}
C{{H}_{2}}{{C}_{6}}{{H}_{5}}\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{H}_{2}}N\,CHC{{O}_{2}}C{{H}_{2}}{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
Compound $'C'$ is
Time Rate (mole $litre^{-1}\,sec^{ -1}$ )
$0$ $2.8 \times {10^{ - 2}}$
$10$ $2.78 \times {10^{ - 2}}$
$20 $ $2.81 \times {10^{ - 2}}$
$30$ $2.79 \times {10^{ - 2}}$
The reaction is
$\begin{array}{*{20}{c}}
{C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - COOH}
\end{array}\xrightarrow{\Delta }(A)\xrightarrow{{C{H_3} - C{H_2}N{H_2}/\Delta }}(B)$
$(B)$ will be :
$CH_3 - CH = CH - CH_3 \xrightarrow{{{O_3}}} A $$\xrightarrow[{Zn}]{{{H_2}O}} B.$
The compound $B$ is