Question
The motion of a particle executing simple harmonic motion is described by the displacement function, $x ( t )= A$ $\cos \left(\omega_t+\omega\right)$.
If the initial $(t=0)$ position of the particle is 1 cm and its initial velocity is $\omega cm / s$, what are its amplitude and initial phase angle? The angular frequency of the particle is $\pi s ^{-1}$. If instead of the cosine function, we choose the sine function to describe the $SHM : x = B \sin (\omega t+a)$, what are the amplitude and initial phase of the particle with the above initial conditions.
If the initial $(t=0)$ position of the particle is 1 cm and its initial velocity is $\omega cm / s$, what are its amplitude and initial phase angle? The angular frequency of the particle is $\pi s ^{-1}$. If instead of the cosine function, we choose the sine function to describe the $SHM : x = B \sin (\omega t+a)$, what are the amplitude and initial phase of the particle with the above initial conditions.
