The negative Zn pole of a Daniel cell, sending a constant current… - Vidyadip

MCQ

The negative $Zn$ pole of a Daniel cell, sending a constant current through a circuit, decreases in mass by $0.13\,g$ in $30$ minutes. If the electrochemical equivalent of $Zn$ and $Cu$ are $32.5$ and $31.5$ respectively, the increase in the mass of the positive $Cu$ pole in this time is .............. $\mathrm{g}$

✓
$0.126$
B
$0.190$
C
$0.141$
D
$0.242$

✓

Answer

Correct option: A.

$0.126$

a
(d) $m = Zi\,t$ $ \Rightarrow $ $\frac{{{m_{Cu}}}}{{{m_{Zn}}}} = \frac{{{Z_{Cu}}}}{{{Z_{Zn}}}}$

${m_{Cu}} = {m_{Zn}}\frac{{{Z_{Cu}}}}{{{Z_{Zn}}}} = 0.13 \times \frac{{31.5}}{{32.5}} = 0.126\,g$

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