MCQ
The nucleus $_{48}^{115}Cd$ after two successive ${\beta ^ - }$ decays will give
- A$_{46}^{115}Pa$
- B$_{49}^{114}In$
- C$_{50}^{113}Sn$
- ✓$_{50}^{115}Sn$
✓
Answer
Correct option: D.
$_{50}^{115}Sn$
d
(d) $_{48}C{{d}^{115}}{{\xrightarrow{_{2(-1}{{\beta }^{o}})}}_{\,50}}S{{n}^{115}}$
(d) $_{48}C{{d}^{115}}{{\xrightarrow{_{2(-1}{{\beta }^{o}})}}_{\,50}}S{{n}^{115}}$
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