MCQ
The nucleus $_{48}^{115}{Cd}$ after two successive $\beta^{-}$ decays will give
 
  • A
     $_{46}^{115} {Pa}$
     
  • B
    $_{49}^{114} {In}$
  • C
    $_{50}^{113} {Sn}$
  • $_{5}^{115}{Sn}$

Answer

Correct option: D.
$_{5}^{115}{Sn}$
(d) $_{5}^{115}{Sn}$

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