MCQ
The nucleus $_{48}^{115}{Cd}$ after two successive $\beta^{-}$ decays will give
- A$_{46}^{115} {Pa}$
- B$_{49}^{114} {In}$
- C$_{50}^{113} {Sn}$
- ✓$_{5}^{115}{Sn}$
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