The number of beats produced per second by two vibrations: $x_1 =x_0$ sin $646\pi t$ and $x_2 = x_0 sin 652 \pi t$ is
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(b) From the given equation ${\omega _1} = 2\pi {n_1} = 646\pi $==>${n_1} = 323$
and ${\omega _2} = 2\pi {n_2} = 652\pi $ ==> ${n_2} = 326$
Hence, beat frequency $ = 326 - 326 = 3$
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