The number of electrons flowing per second in the filament of a $110 \mathrm{~W}$ bulb operating at $220 \mathrm{~V}$ is : (Given $\mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$ )
  • A$31.25 \times 10^{17}$
  • B$6.25 \times 10^{18}$
  • C$6.25 \times 10^{17}$
  • D$1.25 \times 10^{19}$
JEE MAIN 2024, Diffcult
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