MCQ
The number of $sp ^{3}$ hybridised carbons in an acyclic neutral compound with molecular formula $C _{4} H _{5} N$ is.
- ✓$0$ or $1$
- B$2$
- C$3$
- D$4$
$CH _{2}= C = CH = CH = NH$
Zero $sp ^{3}$ carbon
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$N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)} + $ heat
The equilibrium shifts in forward direction