The number which exceeds its positive square root by 12 is - Vidyadip

Question

The number which exceeds its positive square root by $12$ is

✓

Answer

b
(b) Let the required number is $x$

So, $x = \sqrt x + 12\,\,\, \Rightarrow x - 12 = \sqrt x $

==> ${x^2} - 25x + 144 = 0$

==> ${x^2} - 16x - 9x + 144 = 0$$ \Rightarrow x = 16$

=Since $x = 9$ does not hold the condition.

Trick : By inspection, since $16$ exceeds its positive square root i.e.,$4$ by $12$.

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