MCQ
The oxidation number and the electronic configuration of sulphur in ${H_2}S{O_4}$ is
- A$+ 4$ ;$1{s^2}2{s^2}2{p^6}3{s^2}$
- B$+ 2$ ; $1{s^2}2{s^2}2{p^6}3{s^2}3{p^2}$
- C$+ 3$ ; $1{s^2}2{s^2}2{p^6}3{s^2}3{p^1}$
- ✓$+ 6$ ; $1{s^2}2{s^2}2{p^6}$
$2 \times ( + 1) + x + 4 \times ( - 2) = 0$
$ + 2 + x - 8 = 0$; $x = 8 - 2 = + 6$
Electronic configuration of sulphur in ${H_2}S{O_4}$ is
$1{s^2},\,\,2{s^2},\,\,2{p^6}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.