MCQ
The oxidation number of cobalt in $\ce{K[Co(CO)_4]}$ is:
  • A
    $+1$
  • B
    $+3$
  • $–1$
  • D
    $–3$

Answer

Correct option: C.
$–1$
We know that $CO$ is a neutral ligand and $K$ carries a charge of $+1$.
Therefore, the complex can be written as $\ce{K^+[Co(CO)_4]^-}$ .
Therefore, the oxidation number $−$ of $Co$ in the given complex is $-1.$
Hence, option $(iii)$ is correct.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free