MCQ
The oxidation number of Cr in K2Cr2O7 is:
- A+3
- B−3
- C+6
- D−6
✓
Answer
- +6
Explanation:
The sum of the oxidation numbers in a polyatomic ion is equal to the charge on the ion. The oxidation number of simple ions is equal to the charge on the ion. The metals in Group IA (K) atom has an oxidation number of +1. Oxygen usually has an oxidation number of −2.
Oxidation no of Cr in K2Cr2O7
$=2×1+2×\text{x}+7×(−2)=0$
$\text{x}=\frac{14-2}{2}=+6$
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