MCQ
The oxidation number of $H$ in $KH, MgH_2$ and $NaOH$ are respectively
- ✓$-1, -1, +1$
- B$+1, +1, +1$
- C$+2, +11, -2$
- D$-2, -3, -1$
✓
Answer
Correct option: A.
$-1, -1, +1$
a
Metal hydride : $KH, MgH_2$
Oxidation state of $H = -1$
$NaOH$ (Hydroxide)
Oxidation state of $H = +1$
Metal hydride : $KH, MgH_2$
Oxidation state of $H = -1$
$NaOH$ (Hydroxide)
Oxidation state of $H = +1$
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