MCQ
The oxidation state of Cr in K2Cr2O7 is:
- A+4
- B+3
- C+6
- D+5
✓
Answer
- +6
Explanation:
K2Cr2O7
Let the oxidation state of Cr is x.
2(+1) + 2x + 7(−2) = 0
+2 + 2x − 14 = 0
2x − 12 = 0
2x = 12
x = +6
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