MCQ
The oxidation state of $I$ in $IP{O_4}$ is
- A$+1$
- ✓$+3$
- C$+5$
- D$+7$
$x + ( - 3) = 0 \Rightarrow x = + 3$
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$r = \frac{{ - d\left[ A \right]}}{{dt}} = K\,{\left[ A \right]^{\frac{1}{2}}}\,{\left[ B \right]^{\frac{1}{2}}}\,{\left[ C \right]^{\frac{1}{4}}}$
The order of reaction is
$A + B \to C + D$
The enthalpy change and activation energy for the reverse reaction $C + D \to A + B$ are respectively
Phenol $\xrightarrow{{Zn\,\,dust}}X\,\xrightarrow[{Anhyd.\,AlC{l_3}}]{{C{H_3}Cl}}\,Y\xrightarrow{{Alkaline\,\,KMn{O_4}}}\,Z$
the product $Z$ is