MCQ
The oxide which forms dimer is
- A$N_2O_5$
- B$N_2O$
- ✓$NO_2$
- D$N_2O_3$
✓
Answer
Correct option: C.
$NO_2$
c
$NO _2$ has one unpaired electron on Nitrogen, due to which it forms the dimer $N _2 O _4$.
$NO _2$ has one unpaired electron on Nitrogen, due to which it forms the dimer $N _2 O _4$.
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→$\begin{array}{*{20}{c}}
{C{H_3} - C - H} \\
{\,\,\,\,\,||} \\
{\,\,\,\,\,O}
\end{array} \xrightarrow[{\mathop O\limits^\Theta H}]{{HCN}}(A)\xrightarrow[{Hydrolysis}]{{Partial}}(B)$
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{\,\,\,\,\,||} \\
{\,\,\,\,\,O}
\end{array} \xrightarrow[{\mathop O\limits^\Theta H}]{{HCN}}(A)\xrightarrow[{Hydrolysis}]{{Partial}}(B)$
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